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-42x^2+77-35=0
We add all the numbers together, and all the variables
-42x^2+42=0
a = -42; b = 0; c = +42;
Δ = b2-4ac
Δ = 02-4·(-42)·42
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7056}=84$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-84}{2*-42}=\frac{-84}{-84} =1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+84}{2*-42}=\frac{84}{-84} =-1 $
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